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1. INVERSE MATRIX MATHEMATICA HOW TO
2. INVERSE MATRIX MATHEMATICA SOFTWARE
3. INVERSE MATRIX MATHEMATICA CODE
4. INVERSE MATRIX MATHEMATICA PLUS

INVERSE MATRIX MATHEMATICA CODE

3Īnother way to Evaluate a command in an input cell is to click anywhere on the code in the cell, go to Evaluation in the menu at the top of your screen and choose Evaluate Cells from the drop down menu. type 2 + 3 and press Shift-Return to get your answer 5 on a new line.

INVERSE MATRIX MATHEMATICA PLUS

Note that this is also the default mode, so you can just start typing your command without this step, if you click below the plus mark. To enter a command, click on the plus mark in the upper left of your document and choose Mathematica input from the drop down menu.

You can also create a new Notebook, by pressing Command-n on your keyboard. When you open Mathematica, you should open a new Notebook by clicking on File in the menu bar, then follow the path File/New/Notebook.

INVERSE MATRIX MATHEMATICA SOFTWARE

Enter your Notre Dame netID and Password in the fields provided Look for Mathematica on the list of available software Click on More Details and follow the directions to download the Student Version.

Mathematica You may and should download your own free copy of Mathematica from the OIT website Go to the OIT homepage click on Software Downloads in the menu on the left. In this course, we will use the software package Mathematica to find inverses of matrices if we need to and to solve matrix equations such as those shown above. One can find the inverse either by an algebraic formula as with 2 × 2 matrices or using a variation of Gauss-Jordan elimination.

INVERSE MATRIX MATHEMATICA HOW TO

We will not study how to construct the inverses of such matrices for n ≥ 3 in this course, because of time constraints. If the determinant of an n × n matrix, A, is non-zero, then the matrix A has an inverse matrix, A−1. 2Įxample Convert the system of linear equations shown below to a matrix equation of the form AX = B. We then calculate A−1 and multiply the equation AX = B by the matrix A−1 to get and equation of the form X = A−1 B and specific values for x1, x2.

y −3/2 1 7 Performing the cancellation on the left and the multiplication on the right, we get        x −7/2 2 (−7/2)2 + (2)7 7 = y −3/2 1 (−3/2)2 + (1)7 4 and our solution to the system is x = 7, y = 4. Mutiplying the above equation by A−1, we get      x −7/2 2 2 −1 A A =. Since the determinant is non zero, the matrix is invertible and     1 7 −4 −7/2 2 −1 A = −3/2 1 −2 3 −2 1  −2 4 −3 7  −2 Recall to find the inverse of the matrix A = −3 Example In our example, we converted the system of equations  −2x + 4y = 2 −3x + 7y = 7 to matrix form

Lets see how this method works in our example. Namely, we can use matrix algebra to multiply both sides of the equation by A−1, thus getting A−1 AX = A−1 B. , we get two equations 7 equating the elements of each matrix, thus getting our linear system back again: Given a system of linear equations in two unknowns  −2x + 4y = 2 −3x + 7y = 7 We can solve this system of equations using the matrix identity AX = B, if the matrix A has an inverse. When we identify this matrix with the matrix B =. Ve.ve = 1 & vq.vq = 1 & vr.Using matrix inverses and Mathematica to solve systems of equations (Using 2.4, Goldstein, Schneider and Siegel and Mathematica( available on the OIT website)) Given a system of linear equations in two unknowns  −2x + 4y = 2 −3x + 7y = 7 we can write it in matrix form as a single equation AX = B, where       −2 4 x 2 A=, X=, B=. We can verify that minv is the (right) inverse of m like this Assuming[